Mechanical properties of a FeCuSiB alloy with amorphous and/or crystalline structures

Non-isothermal crystallization kinetics and mechanical properties of Al 86 Ni 6 Y 4.5 Co 2 La 1.5 metallic glass powder

“…However, depending on the crystallization products, it is possible that the hardness of partially or fully crystallized metallic glass materials can be higher than that of the fully amorphous state. Similar observations have been observed with other metallic glass systems [29,30]. Table 2 Heat of mixing (kJ/mol) of the component elements in Al86Ni6Y4.5Co2La1.5.…”

Thermal stability, dynamic mechanical analysis and nanoindentation behavior of FeSiB(Cu) amorphous alloys

“…In other words, the large grain size in Cu-free alloy might create a weak interface providing the preferred area for crack nucleation and propagation. Song et al [12,17] observed the similar behavior in hardness and elastic modulus of bulk Fe 76.5 Si 13.5 B 9 Cu 1 alloy and ribbon-type sample with the composition of Fe 74.5 Si 13.5 B 9 Cu 1 Al 2 . Likewise, their study showed that unnecessary annealing for prolonged time, about 2 h, would lead to the significant decrease in hardness.…”

“…Sun et al [12] showed that the strength, elastic modulus and hardness of the FeSiBCu bulk metallic glass with thickness of 3 mm increased upon partial crystallization, reminding the relatively poorer packing efficiency of the amorphous material. Admittedly, amorphous alloys undergo a shear localization and macroscopically brittle failure at room temperature; however, they are still capable of reasonable plastic shear flow in microscale.…”

Mechanism of Mechanically Induced Nanocrystallization of Amorphous FINEMET Ribbons During Milling

“…where q is the ball density (7.8 g cm À3 ); E eff is the effective modulus of the colliding media [27,28] ; m is the pre-collision relative velocity (4 ms À1 for Spex mill and %10 ms À1 for vibrational mill) [14,23,[29][30][31] ; and g p is a geometrical constant which for the collision of ball on curved surface is calculated using the following equation: [14] g p ¼ 0:3521ðb À 1=bÞ 0:6 : ½3…”