2013
DOI: 10.1016/j.ejc.2013.04.005
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2-colorings ink-regulark-uniform hypergraphs

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Cited by 22 publications
(25 citation statements)
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“…Proof Let e be any hyperedge containing v and let Hv be the subhypergraph with e removed from H . By the result of , the hypergraph Hv has a 2‐coloring, say (Av,Bv). If we add v to whichever of Av and Bv doesn’t already contain it, then both Av and Bv are transversals of H .…”
Section: Cubic Graphsmentioning
confidence: 99%
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“…Proof Let e be any hyperedge containing v and let Hv be the subhypergraph with e removed from H . By the result of , the hypergraph Hv has a 2‐coloring, say (Av,Bv). If we add v to whichever of Av and Bv doesn’t already contain it, then both Av and Bv are transversals of H .…”
Section: Cubic Graphsmentioning
confidence: 99%
“…In contrast, Thomassen [28] showed that, for ≥ 4, every -regular graph has two disjoint total dominating sets. It is known [17] that a connected 3-regular 3-uniform hypergraph is almost 2-colorable, in that there is a 2-coloring that 2-colors all but one specified hyperedge. Similarly, a connected cubic graph has a 2-coloring such that each vertex, except possibly two, has both colors in its neighborhood.…”
Section: Cubic Graphsmentioning
confidence: 99%
“…In this article, we study 2‐colorings in k ‐regular k ‐uniform hypergraphs. In the authors presented results on free sets in hypergraphs in Hk for large k . In particular, they showed that for any ε where 0<ε<1 and for sufficiently large k , every hypergraph HscriptHk of order n has a free set of size at least ck×n, where ck=1(prefixln(k)+(prefixln(k))2)/((1ε)k), and so ck1 as k.…”
Section: Resultsmentioning
confidence: 99%
“…We shall need the following lemma. Lemma () If HscriptHk, then there exists a hypergraph HscriptHk1 on the same vertex set such that every edge of H contains an edge of H.…”
Section: Hypergraphs In Hk With Small Kmentioning
confidence: 99%
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