Thermally stable trans‐bis(chelate)‐type Ru(II) complexes are challenging to prepare owing to steric hindrance between the two chelate ligands. Herein, we investigated the isomerization of a heteroleptic cis‐bis(chelate) complex to obtain its trans form. cis‐[Ru(acac)(bpy)(dmso‐S)2](OTf)·0.5H2O (1·(OTf)·0.5H2O; acac− = acetylacetonato; bpy = 2,2’‐bipyridine; dmso = dimethyl sulfoxide; OTf– = CF3SO3–) was prepared by reacting trans(O,S)‐[Ru(bpy)(dmso‐S)2(dmso‐O)2](OTf)2 (P0) with Li(acac) in acetone at 298 K. In 1·(OTf)·0.5H2O, the two labile dmso‐O ligands of P0 were replaced by an acac– ligand. The dihedral angle between the chelate rings of bpy and acac– in 1+ was 76.7°, suggesting steric hindrance between ligands owing to the two bulky dmso‐S ligands at the cis position. 1·(OTf)·0.5H2O was thermally stable in DMSO and acetone; however, in methanol and water, a dmso‐S ligand was dissociated from 1+, and the complex isomerized to trans‐[Ru(acac)(bpy)(dmso‐S)(solvent)]+. Refluxing of 1·(OTf)·0.5H2O in methanol for 18 h, evaporation to dryness under vacuum, and treatment with water yielded trans‐[Ru(acac)(bpy)(dmso‐S)(OH2)](OTf) (2·(OTf)) with excellent purity. 2·(OTf) was characterized by X‐ray crystallography, elemental analysis, and 1H NMR spectroscopy. As expected, steric hindrance was not observed between the trans‐arranged bpy and acac−, and the two chelates laid flat on the equatorial plane in 2+.