“…The diameters of OH À , K + , and Na + ions are 0.220, [39] 0.203, and 0.166 nm, respectively, and, thus, these species could migrate throughout the particles and catalyze the breaking of the C S bonds in petcoke. According to the products of the reaction, Utz et al [40] inferred that the C S bond undergoes homolysis in the presence of the hydroxides at 375 C to generate a free radical, which can be capped by hydrogen or through polymerization, releasing the sulphur as a sulphide or sulphate species. [12][13][14] The sulphur released from petcoke during activation reacts with the alkali ions to form Na 2 S, K 2 S, Na 2 SO 4 , and K 2 SO 4 , which have (pure F I G U R E 5 Scanning electron microscopy (SEM) analysis of polished samples of petcoke activated with KOH but not washed; (A-C) different magnifications of the sample, (D) potassium mapping, and (E) sulphur mapping.…”