2006
DOI: 10.1007/s00022-005-0027-8
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Morse theory for analytic functions on surfaces

Abstract: In this paper we deal with analytic functions f : S → R defined on a compact two dimensional Riemannian surface S whose critical points are semi degenerated (critical points having a non identically vanishing Hessian). To any element p of the set of semi degenerated critical points Q we assign an unique index which can take the values −1, 0 or 1, and prove that Q is made up of finitely many (critical) points with non zero index and embedded circles. Further, we generalize the famous Morse result by showing tha… Show more

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Cited by 4 publications
(5 citation statements)
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“…In our opinion (1.4) is the most relevant results of the Theorems (see [3] for some properties of solutions satisfying (1.17)). In particular we get that there is no u verifying (1.1) such that u(x, y) ∼ u(0, 0) − x 4 − y 4 in a neighborhood of (0, 0)!…”
Section: Introduction and Statement Of The Main Resultsmentioning
confidence: 93%
“…In our opinion (1.4) is the most relevant results of the Theorems (see [3] for some properties of solutions satisfying (1.17)). In particular we get that there is no u verifying (1.1) such that u(x, y) ∼ u(0, 0) − x 4 − y 4 in a neighborhood of (0, 0)!…”
Section: Introduction and Statement Of The Main Resultsmentioning
confidence: 93%
“…[1,26], where hot spots are identified as pixels in the map that have a greater value than their nearestneighbour pixels, and similarly for cold spots. We, however, choose to find the extrema in a manner that is consistent with our method of finding saddle points, so that, for example, we find an equal number of extrema and saddle points, consistent with Morse theory [25]. Using the nearest neighbour-method for identifying extrema returns 180,000 extrema, whereas the critical point method returns 274,000 extrema, which is equal to the number of saddle points found.…”
Section: B)mentioning
confidence: 82%
“…For example, one can naively compute the number of extrema and saddle points by conditioning on being at a critical point, and then compute the relative probabilities of that point being an extremum or a saddle point. This calculation gives the result that saddle points make up 1/ √ 3 ≈ 58% of all critical points, whereas a well-known theorem from Morse theory, and effectively going back to Euler and Poincaré, states that for analytic functions in the plane the numbers of saddle points and extrema are equal, and that they differ by exactly 2 points on the sphere [25].…”
Section: Jcap03(2019)031mentioning
confidence: 99%
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“…Secondly (4.11) shows that at non-zero critical points, we have that the Hessian Hess s does not vanish identically. Hence, any arc in a level subset of s is smooth (one may see [AP05] for more details). As noted in the proof of Lemma 4.2, if p ∈ C, then if p is a saddle point, then the s(p)-level set of s must contain a smooth arc, and hence s attains its global maximum at p. Since s ≥ 0 but has zeroes at only the (finitely many) zeroes of A (see Remark (2.3)), we see that the only critical values obtainable are either global maxima or zeroes (global minima): these account for all the critical points in C.…”
Section: Proof Of Theorem 12mentioning
confidence: 99%