1980
DOI: 10.1016/0375-9474(80)90252-3
|View full text |Cite
|
Sign up to set email alerts
|

Neutron-neutron effective range from quasifree scattering 2H(n, nn)p at 25 MeV

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1

Citation Types

3
3
0

Year Published

1981
1981
2022
2022

Publication Types

Select...
7
1
1

Relationship

1
8

Authors

Journals

citations
Cited by 23 publications
(6 citation statements)
references
References 19 publications
3
3
0
Order By: Relevance
“…(12), (23), and (32) is in perfect agreement with the value of r nn = 2.83(11) fm determined directly from the experiment in [36] and complies well with the value of r nn = 2.85(60) fm from [37]. However, our result in question is in somewhat poorer agreement with the value of r nn = 2.69(27) fm from [38] and the value of r nn = 2.9(4) fm from [39], but remains compatible with them.…”
Section: Resultssupporting
confidence: 89%
“…(12), (23), and (32) is in perfect agreement with the value of r nn = 2.83(11) fm determined directly from the experiment in [36] and complies well with the value of r nn = 2.85(60) fm from [37]. However, our result in question is in somewhat poorer agreement with the value of r nn = 2.69(27) fm from [38] and the value of r nn = 2.9(4) fm from [39], but remains compatible with them.…”
Section: Resultssupporting
confidence: 89%
“…The result is compatible with the value extracted from pp scat tering (38,39,47,48) of 2.84 fm . It is also consistent with more recent results from the analysis of quasi-free nd -+ pnn scattering (63)(64)(65).…”
Section: Neutron-neutron Scattering Lengthsupporting
confidence: 92%
“…The neutron-neu tron effective radius r nn = 2.84(4) fm obtained in this study is practically equal to the value r nn = 2.83(11) fm determined directly from experiment [35] and well agrees with the value r nn = 2.83(16) fm given in [41]. The effective radius obtained by us is in somewhat poorer agreement with the other values, namely, r nn = 2.69 (27) fm [42], r nn = 2.9(4) fm [43], and r nn = 2.65(18) fm [44], not contradicting them.…”
Section: Discussionsupporting
confidence: 72%