1987
DOI: 10.1109/tit.1987.1057363
|View full text |Cite
|
Sign up to set email alerts
|

New bounds on binary linear codes of dimension eight (Corresp.)

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1

Citation Types

0
13
0

Year Published

1992
1992
2009
2009

Publication Types

Select...
4
1

Relationship

0
5

Authors

Journals

citations
Cited by 19 publications
(13 citation statements)
references
References 12 publications
0
13
0
Order By: Relevance
“…By Theorem 2.16, B1 = B2 = 0. Hence the columns of a generator matrix of C are projectively distinct and so must be precisely the 40 distinct points of PG (3,3). Hence C is the simplex code with the required weight enumerator.…”
Section: Determination Of N3(k D) For K _< 4 For All Dmentioning
confidence: 99%
See 2 more Smart Citations
“…By Theorem 2.16, B1 = B2 = 0. Hence the columns of a generator matrix of C are projectively distinct and so must be precisely the 40 distinct points of PG (3,3). Hence C is the simplex code with the required weight enumerator.…”
Section: Determination Of N3(k D) For K _< 4 For All Dmentioning
confidence: 99%
“…However, Problem 2 is the more natural version of the optimal codes problem because the Griesmer bound provides an important lower bound on nq(k, d) which, for given values of q and k, is attained for all sufficiently large values of d. Thus, for given q and k, solving Problem 2 for all d (or solving Problem 1 for all n) becomes a finite one. For q = 2, n2(k, d) is known for k -< 7 and for all d (van Tilborg [18]), while for k = 8, the number of unresolved cases has been reduced to 34 (Dodunekov et al [3], Ytrehus and Helleseth [20]). …”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…In [3] , Dodunekov and Encheva have used this residual code technique to prove the following useful theorem . (2) n the distance of which from C is m , then the matrix…”
Section: Introductionmentioning
confidence: 99%
“…If m ϭ 2 or 3 , then d ϭ 60 or 56 , and the result follows using Lemma 2 . 3 or [3] . If k Ͼ 10 and m ϭ 0 then , by Theorem 2 .…”
Section: Introductionmentioning
confidence: 99%