2023
DOI: 10.1016/j.jmr.2023.107403
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NMR Relaxation by Redfield equation in a spin system I=7/2

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Cited by 4 publications
(1 citation statement)
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“…In the latter case, one should keep in mind that 133 Cs is a spin-7/2 nucleus, whereas 7 Li is a spin-3/2 nucleus. Despite its lowest e Q (−0.343 vs −4.01 fm 2 for 7 Li), 133 Cs undergo the most complex relaxation processes, involving seven transitions (one central and six satellites) against only three for the other nuclei. …”
Section: Resultsmentioning
confidence: 98%
“…In the latter case, one should keep in mind that 133 Cs is a spin-7/2 nucleus, whereas 7 Li is a spin-3/2 nucleus. Despite its lowest e Q (−0.343 vs −4.01 fm 2 for 7 Li), 133 Cs undergo the most complex relaxation processes, involving seven transitions (one central and six satellites) against only three for the other nuclei. …”
Section: Resultsmentioning
confidence: 98%