2009
DOI: 10.1093/imrn/rnp217
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Noether's Problem and the Unramified Brauer Group for Groups of Order 64

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Cited by 26 publications
(31 citation statements)
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“…It follows from [5] that B 0 (G) ∼ = Z/2Z. Application of the algorithm developed in [24] shows that B 0 (G) is generated by the element (g 3 g 2 )(g 4 g 1 ) in G G. The group G is one of the groups of the smallest order that have a nontrivial Bogomolov multiplier [6,5], so it is also of minimal order amongst all B 0 -minimal groups.…”
Section: B 0 -Minimal Groupsmentioning
confidence: 99%
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“…It follows from [5] that B 0 (G) ∼ = Z/2Z. Application of the algorithm developed in [24] shows that B 0 (G) is generated by the element (g 3 g 2 )(g 4 g 1 ) in G G. The group G is one of the groups of the smallest order that have a nontrivial Bogomolov multiplier [6,5], so it is also of minimal order amongst all B 0 -minimal groups.…”
Section: B 0 -Minimal Groupsmentioning
confidence: 99%
“…Making use of recent results on Bogomolov multipliers of p-groups of small orders [13,14,5,6,4,18], we determine the B 0 -minimal families of rank at most 6 for odd primes p, and those of rank at most 7 for p = 2. In stating the proposition, the classifications [16,17] are used.…”
Section: B 0 -Minimal Groupsmentioning
confidence: 99%
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“…Moreover Chu, Hu, Kang and Kunyavskii [CHKK10] investigated the case where G is a group of order 64 as follows. There exist exactly 267 non-isomorphic groups of order 64.…”
Section: Application Of Theorem 123mentioning
confidence: 99%