“…Then the discriminant of f (x, t) become (4t 3 + 28t 2 + 24t + 47) 2 . LetK t be the Galois closure of K t and Gal(K t /Q) D 5 . Then [23]), there exists a constant c f depending only on f such that for every prime q ≥ c f , there is an integer t q with q splits completely in K t for all t ≡ t q mod q.…”