2018
DOI: 10.1090/tran/7374
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Nonsymmetric Macdonald polynomials and a refinement of Kostka–Foulkes polynomials

Abstract: Abstract. We study the specialization of the type A nonsymmetric Macdonald polynomials at t " 0 based on the combinatorial formula of Haglund, Haiman, and Loehr. We prove that this specialization expands nonnegatively into the fundamental slide polynomials, introduced by the author and Searles. Using this and weak dual equivalence, we prove combinatorially that this specialization is a positive graded sum of Demazure characters. We use stability results for fundamental slide polynomials to show that this speci… Show more

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Cited by 20 publications
(39 citation statements)
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“…, x n ] and is a natural generalization of the elementary symmetric functions in the same manner the key polynomials extend the family of Schur polynomials. For example, in a recent paper [3], it is proved that E λ (x; 1, 0) expands positively into key polynomials, where the coefficients are given by the classical Kostka coefficients. This generalizes the classical result that elementary symmetric functions expand positively into Schur polynomials.…”
Section: Discussionmentioning
confidence: 99%
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“…, x n ] and is a natural generalization of the elementary symmetric functions in the same manner the key polynomials extend the family of Schur polynomials. For example, in a recent paper [3], it is proved that E λ (x; 1, 0) expands positively into key polynomials, where the coefficients are given by the classical Kostka coefficients. This generalizes the classical result that elementary symmetric functions expand positively into Schur polynomials.…”
Section: Discussionmentioning
confidence: 99%
“…In particular, these expand positively into key polynomials with Kostka-Foulkes polynomials (in q) as coefficients. There are representation-theoretical explanations for these expansions, as well, see [2,3] and references therein for details.…”
Section: Discussionmentioning
confidence: 99%
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“…Note that a recent combinatorial proof of the key expansion of Eα(x; q, 0) using weak dual equivalence was given in [Ass17].…”
mentioning
confidence: 99%