1974
DOI: 10.1007/bf01078599
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Not every Banach space contains an imbedding ofl p or c0

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Cited by 163 publications
(99 citation statements)
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“…; hence P ∈ P uc . ✷ It has been shown [1] that a Banach space E such that P( k E, K) ≡ P( k E) is reflexive for every k ∈ N has many of the properties of Tsirelson's space T * [17]. In fact, E must be reflexive, and the dual space E * cannot contain copies of ℓ p (1 < p < ∞).…”
Section: Remarkmentioning
confidence: 99%
“…; hence P ∈ P uc . ✷ It has been shown [1] that a Banach space E such that P( k E, K) ≡ P( k E) is reflexive for every k ∈ N has many of the properties of Tsirelson's space T * [17]. In fact, E must be reflexive, and the dual space E * cannot contain copies of ℓ p (1 < p < ∞).…”
Section: Remarkmentioning
confidence: 99%
“…First,Ryszard Komorowski and Nicole Tomczak-Jaegermann [39] showed that a homogeneous Banach space which contains an unconditional basic sequence is isomorphic to a Hubert space. Next, W. T. Gowers [38] proved that a Banach space which contains no unconditional basic sequences must contain a hereditarily indecomposable subspace.…”
Section: Among the Few Classical Problems Remaining Open In This Circmentioning
confidence: 99%
“…The first non-trivial example of an asymptotic 1 space was discovered by Tsirelson [17]. Recent results [6], [7], [15], have shown the necessity of studying the higher ordinal structure of an asymptotic 1 Banach space in order to obtain results on the global structure of its infinite dimensional subspaces.…”
Section: Introductionmentioning
confidence: 99%
“…The key point for the proof of this theorem is to produce for every normalized block sequence (x n ) of the basis, a vector in the linear span of (x n ), whose norm is arbitrarily small yet its support with respect to (x n ) belongs to S ω2 . The dual of the original Tsirelson's space [17] contains no ω 1 spreading model. This is due to the fact that every block sequence is equivalent to a subsequence of the basis.…”
Section: Introductionmentioning
confidence: 99%