“…6. The capacity region for our sand filling approach in this numerical example, is given by 11τ ≤ 1, from Theorem 6, where the bottle neck constraint is (25) which occurs on segment n = 4 (and also on segments n = 1, 2, 3,6,8,9,10,13,14,15,17,19). 6 This can be seen by observing that segment n = 4 has τ [n:n+I] = 10τ + 1τ = 11τ which is the max N −1 n ′ =0 τ [n ′ :n ′ +1] over all segments.…”