“…Then we can obtain its intermediary ciphertext array C according to Equation (5) as C = [211, 132, 239, 53, 58, 240, 44, 45, 220, 207, 217, 89]. Then we can obtain the permutated pixel array P from D by using Equation 4, that is, P = [10,8,2,3,9,11,4,5,12,6,7,1]. By comparing P and P , the permutation array X is recovered as X = [10,8,2,3,9,11,4,5,12,6,7,1].…”