Nuclear data sheets for A = 185

New neutron-rich nuclide185Hf

“…The latter is in qood agreement with the previous result [2], and the former is consistent with the value calculated by using the proton-neutron quasiparticle random-phase approximation (QRPA) with a Gamow-Teller residual interaction [4]. This half-life is in agreement with that obtained above for 18~f and the transition energy is consistent with an excited state in 18~a observed in a 18@W(t,~) reaction study [2]. This half-life is in agreement with that obtained above for 18~f and the transition energy is consistent with an excited state in 18~a observed in a 18@W(t,~) reaction study [2].…”

“…[2] in order to observe possible rapid build up of 185Ta activity and the consequent deca~ Altogether, four separate runs were made. [2] in order to observe possible rapid build up of 185Ta activity and the consequent deca~ Altogether, four separate runs were made.…”

“…[2] in order to observe possible rapid build up of 185Ta activity and the consequent deca~ Altogether, four separate runs were made. The intense Y-rays of 177.59 , 173.91 and 107.80 keV which were assigned to the 185Ta decay were identified through their TI, transition energies and relative intensities [2,3] ( Fig. As a consequence the spectra contained the Z-rays from activities of W and Ta isotopes as well as these from 18~a and Hf radioactive isotopes.…”

Identification ofPt185α activity and study ofAuBingham1, Kassim2, Zhang3 et al. 1991Phys. Rev. C5000View full textAdd to dashboardCite

“…However, a At with a half-life of 4.3 min gives a g2 of 0.63 per degree of freedom whereas a value of 1.75 results from a At with a half-life of the 6.8-min Au isomer; thus, the 4826-keV n probably originates from the ground state. There are two long-lived states [1] in Pt, the ground state with an I of (2 ) and a half-life of 70.9 min and the first excited state with an I of (2 ) and a half-life of 33.0 min. Note in Fig.…”

“…The 33.0-min isomer in Pt has been assigned [1] a spin of (2 ) and thus would be expected to decay to a 2 isomer of Os which has an unknown energy, x. The ground state of is5Pt is believed [1] to be a (2 ); if it decays by n emission it would go to the (2 ) state at 107.6 keV in Os. Coincidence results cannot be used to determine if the 107.6-keV state is populated since there were insufFicient counts in the 4444-keV o; peak to expect to see p rays in coincidence.…”