Open-shell transition metal oxides are capable of developing a rich diversity of electronic phases. The specific features evolving crucially depend on an intricate interplay of various local and long-range electronic interactions. Recently, the 5d transition elements have come into sharp focus because for these elements spin-orbit coupling (SOC) and onsite Coulomb repulsion (U) are on a comparable energy scale. For Ir the t level associated to an octahedral crystal field (CF) is split by SOC, giving rise to a J = spin state and rendering respective oxides like Sr IrO as Mott insulators. Transferring this scenario to iridium(V) oxides would lead to a diamagnetic ground state, J =0. However, reported experimental results do not lend unambiguous support for such an electronic state. Theoretical explanations for the breakdown of the J=0 magnetic state suffer from conspicuous discrepancies. In an attempt to empirically contribute to resolving the puzzle, Bi NaIrO was synthesized in high purity by precipitation from homogeneous solution; it represents an iridium(V) oxide where long range band structure effects and magnetic superexchange are minimized, and the t degeneracy is lifted geometrically. We managed to reduce the strength of paramagnetic response, lending support to a J =0 ground state of Bi NaIrO , exhibiting van Vleck type behavior.