“…Thus, Q 3 × φ Z n is also a regular covering of the complete graph K 4 of order 4. In fact, using results from [9,18,19] one may prove that Q 3 × φ Z n is isomorphic to the following graph G(k, D 2n ). , c), (1, c)), ((0, c), (2, c)), ((0, c), (3, c)), ((1, c), (2, ac)), ((1, c), (3, ab k+1 c)), ((2, c), (3, abc)) | c ∈ D 2n }.…”