2010
DOI: 10.1007/s11425-010-0074-y
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On 3-colorability of planar graphs without adjacent short cycles

Abstract: A short cycle means a cycle of length at most 7. In this paper, we prove that planar graphs without adjacent short cycles are 3-colorable. This improves a result of Borodin et al. (2005).

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Cited by 10 publications
(4 citation statements)
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“…Another relaxation of Nsk3CC is proved by Borodin, Glebov and Raspaud in [14]: every planar graph without triangular cycles of length from 4 to 7 (or, which is equivalent, without triangular cycles of length in {3, 5, 7} or {4, 5, 7}) is 3-colorable. In particular, this implies the 3-colorability of planar graphs having no cycle with the length belonging to any of the sets {4, 5, 7}, {4, 6, 7} or {4, 6, 8} and absorbs the results in [13,15,16,18,19,27,[30][31][32].…”
Section: Conjecture 3 Every Planar Graph With D ∇ 4 and Without Triamentioning
confidence: 83%
“…Another relaxation of Nsk3CC is proved by Borodin, Glebov and Raspaud in [14]: every planar graph without triangular cycles of length from 4 to 7 (or, which is equivalent, without triangular cycles of length in {3, 5, 7} or {4, 5, 7}) is 3-colorable. In particular, this implies the 3-colorability of planar graphs having no cycle with the length belonging to any of the sets {4, 5, 7}, {4, 6, 7} or {4, 6, 8} and absorbs the results in [13,15,16,18,19,27,[30][31][32].…”
Section: Conjecture 3 Every Planar Graph With D ∇ 4 and Without Triamentioning
confidence: 83%
“…The best known bound for k is 7 [9]. A cycle C is triangular if it is adjacent to a triangle other than C. In [6], it is proved that every planar graph without triangular cycles of length from 4 to 7 is 3-colorable, which implies all results in [7,8,9,10,11,21,26,27,28,29].…”
Section: Theorem 6 ([3]mentioning
confidence: 99%
“…有兴趣的读者可参见文献 [14] 以了解更多与 χ-有界的问题相关 的结果. 另外, 读者也可参见文献 [15][16][17][18][19][20] 了解更多关于曲面、图、以及染色的问题、方法与结果.…”
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