2012
DOI: 10.1090/s0002-9939-2011-11008-6
|View full text |Cite
|
Sign up to set email alerts
|

On a discrete version of Tanaka’s theorem for maximal functions

Abstract: Abstract. In this paper we prove a discrete version of Tanaka's theorem [19] for the Hardy-Littlewood maximal operator in dimension n = 1, both in the non-centered and centered cases. For the non-centered maximal operator M we prove that, given a function f : Z → R of bounded variation,where Var(f ) represents the total variation of f . For the centered maximal operator M we prove that, given a function f : Z → R such that f ∈ ℓ 1 (Z),This provides a positive solution to a question of Haj lasz and Onninen [6] … Show more

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1
1

Citation Types

0
58
0

Year Published

2015
2015
2023
2023

Publication Types

Select...
8
1

Relationship

1
8

Authors

Journals

citations
Cited by 57 publications
(58 citation statements)
references
References 17 publications
0
58
0
Order By: Relevance
“…When d = 1, the regularity properties of the discrete maximal type operators were studied by Bober et al [6], Temur [52] and Madrid [49], Carneiro and Madrid [10] and Liu [37]. The following sharp inequalities have been established.…”
Section: 2mentioning
confidence: 99%
“…When d = 1, the regularity properties of the discrete maximal type operators were studied by Bober et al [6], Temur [52] and Madrid [49], Carneiro and Madrid [10] and Liu [37]. The following sharp inequalities have been established.…”
Section: 2mentioning
confidence: 99%
“…Var Mf ≤ C Var f for a universal constant C. Question 1.1 and the validity of Theorem 1.2 were already studied in the discrete setting in [3]. In the present paper, we do not care how small the constant C may be.…”
Section: Introduction and Main Resultsmentioning
confidence: 87%
“…In the present paper, we do not care how small the constant C may be. It is a plausible hypothesis that the inequality holds for C = 1, in the same way as in the non-centered case (see also [3,Question B]). …”
Section: Introduction and Main Resultsmentioning
confidence: 92%
“…As M β f j − M β f ∞ → 0 as j → ∞, there exists j 1 (K) such that C K,j > C K /2 for all j > j 1 (K). 4 For each x ∈ K, let B x,j := B(z x,j , r x,j ) ∈ B β x,j . Then…”
Section: 4mentioning
confidence: 99%