In this appendix reference to equations that appear in the main text are labeled with arabic numerals, e.g. (1). Equations that appear in this appendix are labelled with the letter "A" followed by an arabic numeral, e.g. (A1).
Cellular replication limitsProposition S1. "If the x j (t) are defined by system [1], x k (0) = 1, and x j (0) = 0 for j < k, then ."Proof: From [1] we haveẋ j = 2q x j+1 − x j . Hence, using the initial conditions and integration by parts we find: x j (t) = e −t t 0 2q x j+1 (s) e s ds for 0 < j < k, and x 0 (t) = e (q−1)t t 0 2q x 1 (s)e (1−q)s ds. Given that x k (t) = e −t we can prove by induction that x j (t) = e −t (2qt) k−j (k−j)! for j > 0 and x 0 (t) = 2 k e −t ∞ n=k (qt) n n! . The total cell population X tot (t; q) = k ρ=0 x ρ (t) is then given by:Luria-Delbrück formulation where ψ(z; t, s) = e ize γ(t−s) . Let f (s, z) and g(s) be two functions with continuous second order partial derivates, then:If we make f (s, z) = e ize γ(t−s) −1, we have f (s, 0) = 0 and ∂f (s,0) ∂z = ie γ(t−s) . If we also make g(s) = νX(s), then from the integral expression for Ψ and [A2] we find:Proposition S3. "In the Luria-Delbruck formulation, when the wild type population is modeled with Eq. 3, we have:Proof: Substituting Eq. 3 in the article for X(s) in [A3] we have:For the special case where the growth rate of both populations are equal (γ = 2q − 1), integrating [A6] and simplifying we find [A4]. Expressions of the form e ax Γ(k, bx)dx will show often in our calculations. If a = b, a closed expression for this antiderivative can be found using integration by parts and the fact thatWe can use [A7] to find E[Y (t)] wl when γ = 2q − 1. In this case E(Y (t)) wl is given by Eq. A5.Proposition 4. "In the Luria-Delbruck formulation, when the wild type population is modeled with Eq. 3, we have:(2γ = 2q − 1)Proof: From [5] the characteristic function of the number of mutants Ψ(z; t) = expwhere ψ(z; t, s) = e ize γ(t−s) . Let f (s, z) and g(s) be two functions with continuous second order partial derivates, then:If we make again g(s) = νX(s) and f (s, z) = e ize γ(t−s) − 1, then= −e 2γ(t−s) , and substituting this expression into (A9) we find: Proof: I. From the introduction in the article of the Lea-Coulson formulation, the probability generation function of the number of mutants Y (t) equals:where φ(z; t, s) is given by [19].
) + E[Y (t)] − E[Y (t)]2 . Again making g(s) = νX(s) and f (s, z) = φ(z; t, s) − 1 and using equations [A2] and [A9], we find:Substituting γ by α−β in Eqs.
A3 and A10. It follows that the integrand in [A15] equals E[Y (t)]−V[Y (t)](LD), a n (t, s)z n is the power series representation of φ(z; t, s)−1 centered around z = 0, and X(s) is given by [3], then t 0 νX(s) a n (t, s)z n ds = t 0 νX(s)a n (t, s)z n ds."Proof: The interchange is licit when the growth of the wild type population is exponential, i.e. when X(t) = e δt for any δ > 0 (reference [?]). Hence, since X(t;q) ≤ e (2q−1)t , it follows directly from the dominated convergence theorem that the interchange is also licit when t...