2011
DOI: 10.1080/00927872.2010.514314
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On Finite Complete Presentations and Exact Decompositions of Semigroups

Abstract: Abstract. We prove that given a finite (zero) exact right decomposition (M, T ) of a semigroup S, if M is defined by a finite complete presentation then S is also defined by a finite complete presentation. Exact right decompositions are natural generalizations to semigroups of coset decompositions in groups. As a consequence we deduce that the Zappa-Szép extension of a monoid defined by a finite complete presentation, by a finite monoid is also defined by such a presentation.It is also shown that when a semigr… Show more

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Cited by 4 publications
(3 citation statements)
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References 22 publications
(26 reference statements)
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“…Consider the monoid M 0 obtained from the monoid M defined by Narendran and Otto in [25, page 35] which has undecidable o-conjugacy problem. Since M is defined by a finite complete presentation, the monoid M 0 is also defined by a finite complete presentation by [3,Proposition 3.1]. It can be seen that M does not have a zero.…”
Section: Proposition 42mentioning
confidence: 99%
“…Consider the monoid M 0 obtained from the monoid M defined by Narendran and Otto in [25, page 35] which has undecidable o-conjugacy problem. Since M is defined by a finite complete presentation, the monoid M 0 is also defined by a finite complete presentation by [3,Proposition 3.1]. It can be seen that M does not have a zero.…”
Section: Proposition 42mentioning
confidence: 99%
“…The term 'Zappa-Szep Extension' appears in [2] for the category of semigroups, and the view of such internal products as extensions analogous to traditional split extensions appears in [3]. Early references to such internal products (of subgroups of a given group) appears, for example, in Szep's original paper [19] on the subject, but was studied by others as well, around the same time.…”
Section: Zappa-szep Extensionsmentioning
confidence: 99%
“…As such Q(D 3 ) = H(D 3 ), and that NHol(G) = QHol(G) ∼ = (S 3 × S 3 ) ⋊ C 2 where the C 2 component is that element conjugating λ(D 3 ) to ρ(D 3 ), so that π(Q(G)) is also this same subgroup of order 2. Indeed, if we embed D 3 as S 3 into S 6 then we have λ(S 3 ) = (1, 3)(2, 5) (4,6), (1,4,5)(2, 6, 3) ρ(S 3 ) = (1, 2)(3, 5) (4,6), (1,4,5)(2, 3, 6) QHol(S 3 ) = Hol(S 3 ) τ for any τ ∈ { (1,4), (1,5), (2,3), (2,6), (3,6), (4,5)} so that all π(Q(S 3 )) are isomorphic, which is unsurprising given that Q = H and QHol(S 3 ) = NHol(S 3 ) so that any π(Q(G)) would be isomorphic to T (S 3 ). For D n = x, t | x n = 1, t 2 = 1, xt = tx −1 in general, in [15], we have a complete enumeration of R(D n ) = R(D n , [D n ]).…”
Section: Dihedral Groupsmentioning
confidence: 99%