“…Lemma 5(vi) yields | k c c 16 ( − 1) which is satisfied in each remaining case. Combining Lemma 5(iii) and (v) yields d c = By Lemma 5(iii) r c = 4( − 1).Thus the possibilities for ℓ c d k r ( , , , , ) are(6,16,20,20,2),(10, 28, 32, 36,2), (26, 76, 80, 100, 2). (iv) ℓ x ( , ) = (3, 1).…”