Abstract:If the group G = AB is the product of two abelian subgroups A and B, then G is metabelian by a well-known result of Ito [8], so that the commutator subgroup G' of G is abelian. In the following we are concerned with the following condition:There exists a normal subgroup N^
“…Finally we note that the dual problem of the existence of a non-trivial normal subgroup of the factorized group G = AB ¥= 1 contained in A or B has been studied for instance in [19] and [4]; Zaidev shows for example that this condition holds if A and B are abelian and one of them has finite sectional rank. The example of Howlett in [9] mentioned above also shows that this cannot be extended to the case when A and B are abelian with finite torsion-free rank, and it also becomes false for finite products of two nilpotent groups (see [2] or [8]).…”
Section: Theorem B Let G = a L A T Be A Group Factorized By Finimentioning
Let G be a group factorized by finitely many pairwise permutable nilpotent subgroups. The aim of this paper is to find conditions under which at least one of the factors is contained in a proper normal subgroup of G.
“…Finally we note that the dual problem of the existence of a non-trivial normal subgroup of the factorized group G = AB ¥= 1 contained in A or B has been studied for instance in [19] and [4]; Zaidev shows for example that this condition holds if A and B are abelian and one of them has finite sectional rank. The example of Howlett in [9] mentioned above also shows that this cannot be extended to the case when A and B are abelian with finite torsion-free rank, and it also becomes false for finite products of two nilpotent groups (see [2] or [8]).…”
Section: Theorem B Let G = a L A T Be A Group Factorized By Finimentioning
Let G be a group factorized by finitely many pairwise permutable nilpotent subgroups. The aim of this paper is to find conditions under which at least one of the factors is contained in a proper normal subgroup of G.
“…This combines theorems of B. Amberg (see [1][2][3][4] and [6]) , N.S. Chernikov (see [5]), S. Franciosi, F. de Giovanni (see [3,6,[32][33][34][35][36]), O.H.Kegel (see [8]), J.C.Lennox (see [12]) , D.J.S. Robinson(see [9] and [15]), J.E.…”
In this paper we show that If the soluble-by-finite group G=AB is the product of two polycyclic-by-finite subgroups A and B, then G is polycyclic-by-finite.
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