2017
DOI: 10.1112/plms.12068
|View full text |Cite
|
Sign up to set email alerts
|

On Helson matrices: moment problems, non-negativity, boundedness, and finite rank

Abstract: We study Helson matrices (also known as multiplicative Hankel matrices), that is, infinite matrices of the form M (α) = {α(nm)} ∞ n,m=1 , where α is a sequence of complex numbers. Helson matrices are considered as linear operators on 2 (N). By interpreting Helson matrices as Hankel matrices in countably many variables we use the theory of multivariate moment problems to show that M (α) is non-negative if and only if α is the moment sequence of a measure μ on R ∞ , assuming that α does not grow too fast. We the… Show more

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
2

Citation Types

0
23
0

Year Published

2018
2018
2024
2024

Publication Types

Select...
6

Relationship

2
4

Authors

Journals

citations
Cited by 11 publications
(23 citation statements)
references
References 33 publications
0
23
0
Order By: Relevance
“…Proof. This was proven in [9], but for completeness we repeat the proof. First let us check that w 1/2 H(ζ 1 )w 1/2 is bounded.…”
mentioning
confidence: 67%
See 1 more Smart Citation
“…Proof. This was proven in [9], but for completeness we repeat the proof. First let us check that w 1/2 H(ζ 1 )w 1/2 is bounded.…”
mentioning
confidence: 67%
“…Reduction to weighted integral Hankel operator. We start by recalling a theorem from [9] which establishes a unitary equivalence modulo kernels between a Helson matrix M(a), where a has an integral representation of the type (2.1), and a weighted integral Hankel type operator w 1/2 H(ζ(·+1))w 1/2 with the integral kernel…”
mentioning
confidence: 99%
“…In other words, he asked whether there is an analogue of Nehari's theorem [32] in this context. Helson's question inspired several papers [9,11,25,26,35,36]. Following the program outlined in [26], it was established in [35] that there are bounded Hankel forms that do not extend to bounded functionals on H 1 (D ∞ ).…”
Section: Introductionmentioning
confidence: 99%
“…In the positive direction, it was proved in [25] that if the Hankel form (1) instead satisfies the stronger property of being Hilbert-Schmidt, then its symbol does extend to a bounded functional on H 1 (D ∞ ). Briefly summarizing the most recent development, the result of [35] was generalized in [9], in [11] an analogue of the classical Hilbert matrix was introduced and studied, and in [36] the boundedness of the Hankel form (1) was characterized in terms of Carleson measures in the special case that the form is positive semi-definite.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation