“…It follows that (|A 1 |, |A 2 |, |A 3 |, |A 4 |, |A 5 |) = (1, 1, 1, 3, 3) or (1, 2, 1, 3, 2) or (1, 3, 1, 2, 2). Since λ 1 ≤ 9 3 , for the cases when (1, 1, 1, 3, 3) and (1, 2, 1, 3, 2), we can obtain G 1 from G by deleting λ 1 vertices from A 4 ∪ A 5 . For the case when (1, 3, 1, 2, 2), if λ 1 ≤ 2, we can obtain G 1 from G by deleting λ 1 vertices from A 4 ∪ A 5 .…”