“…The maximum elements in L (3,10) , L (4,7) , and L (9,11) are l (3,10) (v 3 ) = 9 × 3 = 27, l (4,7) (v 1 ) = 4 × 6 = 24, and l (9,11) (v 2 ) = 6 × 4 = 24, respectively, so L (3,10) > L (4,7) and L (3,10) > L (9,11) . In addition, the second maximum elements in L (4,7) and L (9,11) are l (4,7) (v 2 ) = l(v 2 ) = 18 and l(v 1 ) (9,11) = l(v 1 ) = 20 respectively, so L (4,7) < L (9,11) . Thus, v 7 is chosen to add to U and connect with v 4 at this iteration.…”