2011
DOI: 10.1515/jgt.2010.032
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On representations of Artin–Tits and surface braid groups

Abstract: Abstract. We define and study extensions of the Artin and Perron-Vannier representations of braid groups to topological and algebraic generalizations of braid groups. We provide faithful representations of braid groups of oriented surfaces with boundary as automorphisms of finitely generated free groups. The induced representations of such groups as outer automorphisms of finitely generated free groups are still faithful. Also we give a representation of braid groups of closed surfaces as outer automorphisms o… Show more

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Cited by 3 publications
(3 citation statements)
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“…, x n of F n , we have that χ n (α)(x j ) = η −1 (x j ), where χ n (α)(x j ) = ρ A (α)(x j ), identifying any usual braid generator σ i with the corresponding α i . It follows that ρ A (α) is an inner automorphism, therefore α belongs to the center of B n (see for instance [3], Remark 1): more precisely α = ((α n−1 • • • α 1 ) n ) m for some m ∈ Z and ρ A (α)(x j ) = (x…”
Section: Proof Of Theorem 21mentioning
confidence: 99%
See 1 more Smart Citation
“…, x n of F n , we have that χ n (α)(x j ) = η −1 (x j ), where χ n (α)(x j ) = ρ A (α)(x j ), identifying any usual braid generator σ i with the corresponding α i . It follows that ρ A (α) is an inner automorphism, therefore α belongs to the center of B n (see for instance [3], Remark 1): more precisely α = ((α n−1 • • • α 1 ) n ) m for some m ∈ Z and ρ A (α)(x j ) = (x…”
Section: Proof Of Theorem 21mentioning
confidence: 99%
“…It follows that ρ A (α) is an inner automorphism, therefore α belongs to the center of B n (see for instance [3], Remark 1): more precisely α = ((α n−1 . .…”
mentioning
confidence: 99%
“…A straightforward calculation shows that τ 4 (H) = (1, 3), (2,4) , which is isomorphic to S 2 × S 2 . Taking B 2,2 (RP 2 ) to be τ −1 4 ( (1, 3), (2,4) ), the restriction to H of the projection p : B 2,2 (RP 2 ) −→ B 2 (RP 2 ) given geometrically by forgetting the second and fourth strings is an isomorphism. This follows since ker(p) is torsion free and B 2 (RP 2 ) ∼ = Q 16 [35].…”
Section: Appendix On Exact Sequencesmentioning
confidence: 99%