2017
DOI: 10.1016/j.ejc.2017.06.018
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On solution-free sets of integers

Abstract: Abstract. Given a linear equation L, a set A ⊆ [n] is L-free if A does not contain any 'non-trivial' solutions to L. In this paper we consider the following three general questions:

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Cited by 9 publications
(27 citation statements)
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“…(i) If q divides p and p + q ≤ rq then µ L (n) = ⌈(q − 1)n/q⌉; (ii) If q divides p and p + q ≥ rq then µ L (n) = ⌈(p + q − r)(n − a)/(p + q)⌉ + a where a is the unique non-negative integer 0 ≤ a < q such that n − a is divisible by q; (iii) If q does not divide p, t > 1 and r > (r 1 r 2 − r 1 − r 2 + 4)r 2 r 1 + 1 + r 2 − 1 r 2 1 + (r 1 − 1)(r 2 − 1) then µ L (n) = ⌈(t − 1)n/t⌉. Theorem 2(ii) was already proven (for large enough n) in [14] in the special case when r = 1. (Note though that our work in [14] determines µ L (n) for many equations L not covered by Theorem 2.)…”
Section: Introductionmentioning
confidence: 83%
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“…(i) If q divides p and p + q ≤ rq then µ L (n) = ⌈(q − 1)n/q⌉; (ii) If q divides p and p + q ≥ rq then µ L (n) = ⌈(p + q − r)(n − a)/(p + q)⌉ + a where a is the unique non-negative integer 0 ≤ a < q such that n − a is divisible by q; (iii) If q does not divide p, t > 1 and r > (r 1 r 2 − r 1 − r 2 + 4)r 2 r 1 + 1 + r 2 − 1 r 2 1 + (r 1 − 1)(r 2 − 1) then µ L (n) = ⌈(t − 1)n/t⌉. Theorem 2(ii) was already proven (for large enough n) in [14] in the special case when r = 1. (Note though that our work in [14] determines µ L (n) for many equations L not covered by Theorem 2.)…”
Section: Introductionmentioning
confidence: 83%
“…Theorem 2(ii) was already proven (for large enough n) in [14] in the special case when r = 1. (Note though that our work in [14] determines µ L (n) for many equations L not covered by Theorem 2.) Previously, Hegarty [15] proved Theorem 2(i) in the case when p = q.…”
Section: Introductionmentioning
confidence: 83%
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“…For sum-free subsets, that is A = ( 1 1 −1 ), it is also easy to see that π(A) = 1/2. Hancock and Treglown [16] very recently extended this to matrices of the form A = ( p q −r ) where p, q, r ∈ N such that p ≥ q ≥ r. Unfortunately, unlike the Erdős-Stone-Simonovits Theorem [17,18] in the graph case, no exact characterization of π(A) is known for arbitrary matrices A. However, the following lemma shows that one can still easily bound this value away from 1 for every irredundant and positive matrix.…”
Section: Preliminariesmentioning
confidence: 99%