2017
DOI: 10.37236/6181
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On Stacked Triangulated Manifolds

Abstract: We prove two results on stacked triangulated manifolds in this paper: (a) every stacked triangulation of a connected manifold with or without boundary is obtained from a simplex or the boundary of a simplex by certain combinatorial operations; (b) in dimension d ≥ 4, if ∆ is a tight connected closed homology d-manifold whose ith homology vanishes for 1 < i < d − 1, then ∆ is a stacked triangulation of a manifold. These results give affirmative answers to questions posed by Novik and Swartz and by Effenberger.M… Show more

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Cited by 11 publications
(16 citation statements)
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“…The first main result of this paper (in Section 4) is an extension of Proposition 1.6: If a closed, triangulated 3-manifold is tight with respect to a field of odd characteristic then it must be (orientable, neighbourly and) stacked. This result answers Question 4.5 of [9] affirmatively, in the case of odd characteristic. As a consequence of Proposition 1.7 it follows that the Kühnel-Lutz conjecture is true in a special case, namely, if char(F) = 2 then any F-tight, closed, triangulated 3-manifold is strongly minimal.…”
Section: Introductionsupporting
confidence: 73%
See 1 more Smart Citation
“…The first main result of this paper (in Section 4) is an extension of Proposition 1.6: If a closed, triangulated 3-manifold is tight with respect to a field of odd characteristic then it must be (orientable, neighbourly and) stacked. This result answers Question 4.5 of [9] affirmatively, in the case of odd characteristic. As a consequence of Proposition 1.7 it follows that the Kühnel-Lutz conjecture is true in a special case, namely, if char(F) = 2 then any F-tight, closed, triangulated 3-manifold is strongly minimal.…”
Section: Introductionsupporting
confidence: 73%
“…Example 6.2 shows that Proposition 2.10 does not hold in dimension 3. From [9] we know the following.…”
Section: Preliminaries On Stacked and Tight Triangulationsmentioning
confidence: 99%
“…Each such manifold is obtained by starting with several disjoint boundary complexes of the d-simplex and repeatedly forming connected sums and/or handle additions. Similarly, each 1-stacked manifold with boundary (of dimension ≥ 2) is obtained by starting with a number of d-simplices and repeatedly forming connected unions and/or handle additions; see [18] for more details. Therefore, all 1-stacked manifolds without boundary are spheres or connected sums of sphere bundles over S 1 .…”
Section: R-stacked Manifolds and The Cases Of Equalitymentioning
confidence: 99%
“…By Theorem 1.2, X is stacked. But, by Corollary 3.13 (case d = 3) of [8], any stacked triangulation of a closed 3-manifold can be obtained from a stacked 3-sphere by a finite sequence of elementary handle additions. It is easy to see by an induction on the number k of handles added that X triangulates either S 3 (k = 0) or (S 2 × S 1 ) #k or (S 2 × − S 1 ) #k (k ≥ 1).…”
Section: Proofsmentioning
confidence: 99%