2016
DOI: 10.4171/qt/83
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On the asymptotic expansion of the Kashaev invariant of the $5_2$ knot

Abstract: We give a presentation of the asymptotic expansion of the Kashaev invariant of the 52 knot. As the volume conjecture states, the leading term of the expansion presents the hyperbolic volume and the Chern-Simons invariant of the complement of the 52 knot. Further, we obtain a method to compute the full Poincare asymptotics to all orders of the Kashaev invariant of the 52 knot.

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Cited by 38 publications
(68 citation statements)
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“…For a knot/link complement, there are several developed state-integral models [29,30,31]. For our purpose, in particular, we will use the state-integral model developed in [30,32] (see also [33,34,35,36] for discussion of higher order terms for knot complements). This result was motivated from complex Chern-Simons theory [1,2]; in our context this is natural since Jones polynomial is nothing but the vacuum expectation value of the Wilson line in Chern-Simons theory [4] and an interpretation for the volume conjecture (for a link complement) is provided in [37].…”
Section: State-integral Model For Closed 3-manifoldsmentioning
confidence: 99%
“…For a knot/link complement, there are several developed state-integral models [29,30,31]. For our purpose, in particular, we will use the state-integral model developed in [30,32] (see also [33,34,35,36] for discussion of higher order terms for knot complements). This result was motivated from complex Chern-Simons theory [1,2]; in our context this is natural since Jones polynomial is nothing but the vacuum expectation value of the Wilson line in Chern-Simons theory [4] and an interpretation for the volume conjecture (for a link complement) is provided in [37].…”
Section: State-integral Model For Closed 3-manifoldsmentioning
confidence: 99%
“…We put q = exp(2π √ −1/N ), and put (x) n = (1 − x)(1 − x 2 ) · · · (1 − x n ) for n ≥ 0. It is known [18] (see also [20]) that for any n, m with n ≤ m, (q) n (q) N −n−1 = N, (4) ∑ n≤k≤m 1 (q) m−k (q) k−n = 1.…”
Section: Integral Presentation Of (Q) Nmentioning
confidence: 99%
“…More precisely, as for the convergence of 1 N φ(t) as N → ∞, we recall the following proposition. [20]). We fix any sufficiently small δ > 0 and any M > 0.…”
Section: Integral Presentation Of (Q) Nmentioning
confidence: 99%
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