2019
DOI: 10.1088/1361-6382/ab50a8
|View full text |Cite
|
Sign up to set email alerts
|

On the charged Riemannian Penrose inequality with charged matter

Abstract: Throughout the literature on the charged Riemannian Penrose inequality, it is generally assumed that there is no charged matter present; that is, the electric field is divergence-free. The aim of this article is to clarify when the charged Riemannian Penrose inequality holds in the presence of charged matter, and when it does not. First we revisit Jang’s proof of the charged Riemannian Penrose inequality to show that under suitable conditions on the charged matter, this argument still carries though. In partic… Show more

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

0
11
0

Year Published

2020
2020
2024
2024

Publication Types

Select...
5
2

Relationship

2
5

Authors

Journals

citations
Cited by 9 publications
(11 citation statements)
references
References 25 publications
0
11
0
Order By: Relevance
“…The Riemannian case of this has also been settled. Under the assumption that the horizon is connected, this result follows from an old argument of Jang [13] when combined with the more recent development of weak inverse mean curvature flow by Huisken and Ilmanen [9] (see also [18]). The case of a disconnected horizon is more subtle when one includes electric charge and some extra care must be taken.…”
Section: Introductionmentioning
confidence: 68%
See 2 more Smart Citations
“…The Riemannian case of this has also been settled. Under the assumption that the horizon is connected, this result follows from an old argument of Jang [13] when combined with the more recent development of weak inverse mean curvature flow by Huisken and Ilmanen [9] (see also [18]). The case of a disconnected horizon is more subtle when one includes electric charge and some extra care must be taken.…”
Section: Introductionmentioning
confidence: 68%
“…We are now ready to state the three versions of the charged Riemannian Penrose inequality that we require. Theorem 2.1 ( [14,18]). Let (M, g, E) be a charged asymptotically flat 3-manifold satisfying R(g) ≥ 2|E| 2 + 4|∇ • E|, containing an outermost minimal surface Σ, and assume that ∇ • E is compactly supported.…”
Section: Setup and Definitionsmentioning
confidence: 99%
See 1 more Smart Citation
“…This is Geroch monotonicity [32], which leads to a proof of the Penrose inequality for a single black hole. A version of the above arguments holds for the Penrose inequality with charge [43,44,48,58] using the charged Hawking mass [29].…”
Section: 2mentioning
confidence: 99%
“…Furthermore, results are typically stated within the framework of initial data sets for the Einstein equations that satisfy the relevant energy condition, and the inclusion of angular momentum/charge requires the absence of angular momentum/charge density outside the horizon in addition to axisymmetry (which is only needed for angular momentum). The Penrose inequality has been established in the case of maximal data by Bray [8] and Huisken-Ilmanen [34], and charge was added in [40,44]. The inclusion of angular momentum is much more difficult and has not yet been established, although see [3,38] for partial results.…”
Section: Introductionmentioning
confidence: 99%