We determine the combinatorial depth of certain subgroups of simple Suzuki groups Sz(q), among others, the depth of their maximal subgroups. We apply these results to determine the ordinary depth of these subgroups.L. H ÉTHELYI, E. HORV ÁTH, AND F. PET ÉNYIIn [1] the depth of a partially ordered set X is introduced, as the length of a largest chain in X, and δ is defined as the depth of U ∞ (H, G). The symbol δ * denotes the smallest positive integer k such that Core G (H) can be written as the intersection of k conjugates of H, and δ * denotes the smallest positive integer k such that the intersection of any k distinct conjugates of H is equal to Core G (H).Theorem 1.2. [1, Thm 3.11] Let G be a finite group, H a subgroup of G andNow let us remind the reader to the notion of ordinary depth of a subgroup H in the finite group G. We say that the depth of the group algebra inclusionFurthermore CH is said to have depth 2n + 1 in CG if the same assertion holds for CH − CH-bimodules. Finally CH has depth 1 in CG if CG is isomorphis to a direct summand of ⊕ a i=1 CH as CH − CH bimodules. The minimal depth of group algebra inclusion CH ⊆ CG is called (minimal) ordinary depth of H in G, which we denote by d(H, G). This is well defined.This depth can be obtained from the so called inclusion matrix M . If χ 1 , . . . , χ s are all irreducible characters of G and ψ 1 , . . . , ψ r are all irreducible characters of H, then m i,j := (ψ G i , χ j ). The "powers" of M are defined by M 2l := M 2l−1 M T and M 2l+1 := M 2l M The odinary depth d(H, G) can be obtained as the smallest integer n such that M n+1 ≤ aM n−1 . This is well defined. The results on characters in [2] help to determine d(H, G). Two irreducible characters α, β ∈ Irr(H) are related, α ∼ β, if they are constituents of some χ H , for χ ∈ Irr(G). The distance d(α, β) = m is the smallest integer m such that there is a chain of irreducible characters of H such that α = ψ 0 ∼ ψ 1 . . . ∼ ψ m = β. If there is no such chain then d(α, β) = −∞ and if α = β then the distance is zero. If X is the set of irreducible constituents of χ H then m(χ) := max α∈Irr(H) min ψ∈X d(α, ψ). The following results from [2] will be useful.