2017
DOI: 10.1016/j.comgeo.2017.07.002
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On the existence of ordinary triangles

Abstract: Let P be a finite point set in the plane. A c-ordinary triangle in P is a subset of P consisting of three non-collinear points such that each of the three lines determined by the three points contains at most c points of P . Motivated by a question of Erdős, and answering a question of de Zeeuw, we prove that there exists a constant c > 0 such that P contains a c-ordinary triangle, provided that P is not contained in the union of two lines. Furthermore, the number of c-ordinary triangles in P is Ω(|P |).2010 M… Show more

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Cited by 2 publications
(5 citation statements)
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“…The proof for the first case follows that of Fulek et al [4]. Our main contribution is finding a better argument for the second case.…”
Section: Proof Of Theorem 11supporting
confidence: 69%
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“…The proof for the first case follows that of Fulek et al [4]. Our main contribution is finding a better argument for the second case.…”
Section: Proof Of Theorem 11supporting
confidence: 69%
“…With an interest in studying ordinary conics [2], de Zeeuw asked whether there exists an integer c such that every set P of points not contained in the union of two lines contains a c-ordinary triangle, that is, three non-collinear points of P , where each line spanned by the points is c-ordinary. Fulek, Nassajian Mojarrad, Naszódi, Solymosi, Stich, and Szedlák [4] answered in the affirmative for n sufficiently large, and showed one may take c = 12000. We improve this to c = 11.…”
Section: Introductionmentioning
confidence: 93%
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“…Fulek et al [10] proved that there exists a c > 0 such that if a finite point set in R 2 is not covered by two lines, then there are three points in the set such that all three lines spanned by them contain at most c points (they call this a c-ordinary triangle). Their proof gave c = 12000.…”
Section: Construction 13 (Fermat Configuration)mentioning
confidence: 99%
“…Compare this with the Szemerédi-Trotter theorem [23,24,25] in R 2 , which implies that the number of lines with at least k points is at most cn 2 /k 3 for some constant c (when k < √ n). This c is fairly large ( [10] states c = 125), so (9) does better for small k (specifically k ≤ 58).…”
Section: Spanned Lines In Rmentioning
confidence: 99%