2016
DOI: 10.4310/mrl.2016.v23.n6.a1
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On the (non)existence of symplectic resolutions of linear quotients

Abstract: Abstract. We study the existence of symplectic resolutions of quotient singularities V /G, where V is a symplectic vector space and G acts symplectically. Namely, we classify the symplectically irreducible and imprimitive groups, excluding those of the form K S2 where K < SL2(C), for which the corresponding quotient singularity admits a projective symplectic resolution. As a consequence, for dim V = 4, we classify all symplectically irreducible quotient singularities V /G admitting a projective symplectic reso… Show more

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Cited by 15 publications
(17 citation statements)
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“…In this paper, we show that these questions have affirmative answers for linear quotient singularities (which rarely admit symplectic resolutions, as explained in [BS13]) and that (1) and (2) have affirmative answers for hypertoric varieties, and we explicitly compute the decompositions. For the case where X is the nilpotent cone of a semisimple Lie algebra (or its Kostant-Slodowy slices), see Remark 11 for a discussion.…”
Section: Introductionmentioning
confidence: 76%
“…In this paper, we show that these questions have affirmative answers for linear quotient singularities (which rarely admit symplectic resolutions, as explained in [BS13]) and that (1) and (2) have affirmative answers for hypertoric varieties, and we explicitly compute the decompositions. For the case where X is the nilpotent cone of a semisimple Lie algebra (or its Kostant-Slodowy slices), see Remark 11 for a discussion.…”
Section: Introductionmentioning
confidence: 76%
“…As noted by the referee, choosing a suitable normal subgroup K of G may allow one to apply the geometric techniques of [5] in order to show that some of the remaining open cases of symplectically primitive but complex imprimitive groups do not give rise to quotient singularities admitting a symplectic resolution. Specifically, if there exists a symplectic resolution Y → V /K such that the action of G/K on V /K lifts to Y , then the existence of particularly bad singularities on Y /(G/K ) implies that V /G cannot admit a symplectic resolution.…”
Section: Remark 15mentioning
confidence: 99%
“…In this section we show that for the group W (S 2 ) of [11, Table III] there is no symplectic resolution of the corresponding linear quotient. This group is one of the few symplectically and complex primitive groups; we follow the same strategy used in [5] to treat these groups. Namely, we are going to show, or rather compute that there is a subgroup of W (S 2 ), say H , which is the stabilizer of a vector.…”
Section: Theorem 45 If There Existsmentioning
confidence: 99%
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