1999
DOI: 10.1007/s002200050747
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On the Non-Integrability of the Stark-Zeeman Hamiltonian System

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Cited by 8 publications
(5 citation statements)
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“…Proceeding as in the proof of Lemma 2, we conclude that under our assumption equation (21) is solvable if and only if it has a solution of the form y = P/(z − 1) m+2 with P a polynomial of degree m. Following the method of [23], we make the change of variables y = Y /(z − 1) m+2 in (21) and compute the recurrence relation satisfied by the coefficients of a power series solution Y = u n z n at zero. The recurrence is:…”
Section: Lemma 3 If K = (M + 2)mentioning
confidence: 86%
See 1 more Smart Citation
“…Proceeding as in the proof of Lemma 2, we conclude that under our assumption equation (21) is solvable if and only if it has a solution of the form y = P/(z − 1) m+2 with P a polynomial of degree m. Following the method of [23], we make the change of variables y = Y /(z − 1) m+2 in (21) and compute the recurrence relation satisfied by the coefficients of a power series solution Y = u n z n at zero. The recurrence is:…”
Section: Lemma 3 If K = (M + 2)mentioning
confidence: 86%
“…In Section 6, we study the exceptional case a = −k and conclude that the MoralesRamis method yields no obstruction to integrability, whereas dynamical analysis seems to indicate that the system is not completely integrable. The Morales-Ramis theory was applied to study the integrability of many Hamiltonian systems, see examples in book [17] and in papers [19,20,21,22,23,24,25,26,27,28]. The differential Galois approach was used also for proving non-integrability of non-Hamiltonian systems, see [29,30,31].…”
Section: Theoremmentioning
confidence: 99%
“…If (u) is meromorphic function of u in U and satisfies (7), then (u) is called a meromorphic first integral of system (6). Generally speaking, system (6) is integrable if it has a sufficiently rich set of first integrals such that its solutions can be expressed by these first integrals.…”
Section: Preliminaries On Galois Theorymentioning
confidence: 99%
“…Proof. Local computation shows that equation (21) has logarithms in its formal solutions at zero and infinity whenever k = 0. Thus, as we know from Remark 2, if the equation has a Liouvillian solution, then it must be an exponential one, i.e.…”
Section: Non-integrability Of the Classical Spring-pendulummentioning
confidence: 99%
“…In Section 6, we study the exceptional case a = −k and conclude that the Morales-Ramis method yields no obstruction to integrability, whereas dynamical analysis seems to indicate that the system is not completely integrable. The Morales-Ramis theory was applied to study the integrability of many Hamiltonian systems, see examples in book [17] and in papers [19,20,21,22,23,24,25,26,27,28]. The differential Galois approach was used also for proving non-integrability of non-Hamiltonian systems, see [29,30,31].…”
Section: Introductionmentioning
confidence: 99%