2010
DOI: 10.1017/s0021900200006690
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On the number of runs for Bernoulli arrays

Abstract: We introduce and motivate the study of (n + 1) × r arrays X with Bernoulli entries X k,j and independently distributed rows. We study the distribution of S n = r j =1 n k=1 X k,j X k+1,j , which denotes the number of consecutive pairs of successes (or runs of length 2) when reading the array down the columns and across the rows. With the case r = 1 having been studied by several authors, and permitting some initial inferences for the general case r > 1, we examine various distributional properties and represen… Show more

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Cited by 2 publications
(5 citation statements)
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“…Proof. It follows directly from representation (12) and Theorem 1 that the probability function of S n in the context here of a Pólya urn is given by the above equations with B n,k,m = E[Z m a n,k (Z)], where Z This is verified by establishing that (i) Z = 4θ(1 − θ) ∼ Beta(2b/s − 1, 1 2 ) whenever θ ∼ Beta(b , b ), and (ii) by directly evaluating (14) via (15).…”
Section: Corollary 3 Letmentioning
confidence: 82%
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“…Proof. It follows directly from representation (12) and Theorem 1 that the probability function of S n in the context here of a Pólya urn is given by the above equations with B n,k,m = E[Z m a n,k (Z)], where Z This is verified by establishing that (i) Z = 4θ(1 − θ) ∼ Beta(2b/s − 1, 1 2 ) whenever θ ∼ Beta(b , b ), and (ii) by directly evaluating (14) via (15).…”
Section: Corollary 3 Letmentioning
confidence: 82%
“…which implies that S n ∼ Bin(n, 1 2 ). For part (b), begin with standard operations to express α n as a polynomial in t. Write the λ 1 and λ 2 of Corollary 1 as λ 1 = (t + )/2 and λ 2 = (t − )/2, with = ρ + t 2 (1 − ρ), so that λ 1 − λ 2 = , and…”
Section: Theorem 1 Under Assumption (7)mentioning
confidence: 98%
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