2019
DOI: 10.14232/actasm-018-279-1
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On the pairs of completely multiplicative functions satisfying some relation

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Cited by 4 publications
(4 citation statements)
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“…This was proved in [20] by the first author. Later, the result was generalized by Kátai and Phong [17] who proved that if f,g0pt:double-struckNS1$f,g\colon \mathbb {N}\rightarrow S^1$ are completely multiplicative and nxfalse|g(2n+1)goodbreak−zf(n)false|=ofalse(xfalse)$$\begin{align} \sum _{n\leqslant x}|g(2n+1)-zf(n)|=o(x) \end{align}$$for some complex number z , then f(n)=g(n)=nit$f(n)=g(n)=n^{it}$. Since in the function field setting there are two varieties of Archimedean characters, namely eθ$e_{\theta }$ and short interval characters ξ, our classification of completely multiplicative functions satisfying (6) (and in fact more generally (7)) in function fields takes a slightly different form.…”
Section: Introduction and Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…This was proved in [20] by the first author. Later, the result was generalized by Kátai and Phong [17] who proved that if f,g0pt:double-struckNS1$f,g\colon \mathbb {N}\rightarrow S^1$ are completely multiplicative and nxfalse|g(2n+1)goodbreak−zf(n)false|=ofalse(xfalse)$$\begin{align} \sum _{n\leqslant x}|g(2n+1)-zf(n)|=o(x) \end{align}$$for some complex number z , then f(n)=g(n)=nit$f(n)=g(n)=n^{it}$. Since in the function field setting there are two varieties of Archimedean characters, namely eθ$e_{\theta }$ and short interval characters ξ, our classification of completely multiplicative functions satisfying (6) (and in fact more generally (7)) in function fields takes a slightly different form.…”
Section: Introduction and Resultsmentioning
confidence: 99%
“…This was proved in [20] by the first author. Later, the result was generalized by Kátai and Phong [17] who proved that if 𝑓, g ∶ ℕ → 𝑆 1 are completely multiplicative and…”
mentioning
confidence: 97%
“…Shortly after Klurman's 2017 result became known, Kátai and Phong [2] used his result to prove that if f, g ∈ M *…”
Section: Consequences Of Klurman's Resultsmentioning
confidence: 99%
“…then f (n) = n it for some real number t. This was proved in [16]. Later, the result was generalized by Kátai and Phong [13] who proved that if f, g : N → S 1 are completely multiplicative and…”
Section: Remarksmentioning
confidence: 88%