2016
DOI: 10.1007/s00453-016-0200-5
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On the Recognition of Fan-Planar and Maximal Outer-Fan-Planar Graphs

Abstract: Abstract. Fan-planar graphs were recently introduced as a generalization of 1-planar graphs. A graph is fan-planar if it can be embedded in the plane, such that each edge that is crossed more than once, is crossed by a bundle of two or more edges incident to a common vertex. A graph is outer-fan-planar if it has a fan-planar embedding in which every vertex is on the outer face. If, in addition, the insertion of an edge destroys its outer-fan-planarity, then it is maximal outer-fan-planar. In this paper, we pre… Show more

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Cited by 26 publications
(17 citation statements)
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References 35 publications
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“…For 1-planarity this was proved by Grigoriev and Bodlaender [24] and by Korzhik and Mohar [28], and improved to hold for graphs of bounded bandwidth, pathwidth, or treewidth [4], for near planar graphs [15], and for 3-connected 1-planar graphs with a given rotation system [3]. Moreover, the recognition of right angle crossing graphs (RAC) [1] and of fan-planar graphs [5,6] is N P-hard. On the other hand, Eades et al [21] introduced a linear time testing algorithm for (planar) maximal 1-planar graphs that are given with a rotation system.…”
Section: Introductionmentioning
confidence: 89%
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“…For 1-planarity this was proved by Grigoriev and Bodlaender [24] and by Korzhik and Mohar [28], and improved to hold for graphs of bounded bandwidth, pathwidth, or treewidth [4], for near planar graphs [15], and for 3-connected 1-planar graphs with a given rotation system [3]. Moreover, the recognition of right angle crossing graphs (RAC) [1] and of fan-planar graphs [5,6] is N P-hard. On the other hand, Eades et al [21] introduced a linear time testing algorithm for (planar) maximal 1-planar graphs that are given with a rotation system.…”
Section: Introductionmentioning
confidence: 89%
“…Proof If C R is good, then the degree vector of the four vertices that match the vertices of the inner cycle of CC is (4,4,5,5,5,5,6). The degree vector (5,5,5,5,5,6,6) implies a blocking red edge and −−→ H (x) = (4, 4, 5, 5, 6, 6, 6) implies a black edge between two opposite neighbors of a center, which violates CC.…”
Section: Lemmamentioning
confidence: 97%
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