1994
DOI: 10.4064/fm-144-2-143-161
|View full text |Cite
|
Sign up to set email alerts
|

On the representation type of tensor product algebras

Abstract: The representation type of tensor product algebras of finite-dimensional algebras is considered. The characterization of algebras A, B such that A ⊗ B is of tame representation type is given in terms of the Gabriel quivers of the algebras A, B.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

0
26
0

Year Published

2001
2001
2024
2024

Publication Types

Select...
8

Relationship

0
8

Authors

Journals

citations
Cited by 44 publications
(26 citation statements)
references
References 19 publications
0
26
0
Order By: Relevance
“…With these notations we have an isomorphism of k-algebras kQ /I ⊗ k kQ /I kQ/I (see [12]). However, note that since the natural projections from (Q, I, x) to (Q , I , x ) and (Q , I , x ) are not morphisms of pointed bound quivers, the product quiver is not the product of (Q , I , x ) and (Q , I , x ) in the category of pointed bound quivers.…”
Section: Productsmentioning
confidence: 99%
See 1 more Smart Citation
“…With these notations we have an isomorphism of k-algebras kQ /I ⊗ k kQ /I kQ/I (see [12]). However, note that since the natural projections from (Q, I, x) to (Q , I , x ) and (Q , I , x ) are not morphisms of pointed bound quivers, the product quiver is not the product of (Q , I , x ) and (Q , I , x ) in the category of pointed bound quivers.…”
Section: Productsmentioning
confidence: 99%
“…Following [12], we define the product quiver Q = Q ⊗ Q as follows. The vertex set Q 0 is simply Q 0 × Q 0 , whereas the arrow set is…”
Section: Productsmentioning
confidence: 99%
“…Proof. We know from [11] that if B is a triangular basic algebra then the enveloping algebra B e is also triangular and basic. Then we infer by Theorem 4.2 that A e T ( 1 , 2 )(B e ).…”
Section: Applications To the Enveloping Algebrasmentioning
confidence: 99%
“…Proof. We know from [11] that A o ⊗ K B is representation-infinite and A e is representation-infinite. But A is a left-right projective A-bimodule which is not projective.…”
Section: 5mentioning
confidence: 99%
“…Then by Theorem 2 all A-bimodules in the whole connected component C of Γ A e containing an indecomposable direct summand of A are left-right projective. Thus lrp(A e ) is representation-infinite, because mod(A e ) is representation-infinite (see [11]). Furthermore, Theorem 1 yields that lrp(A o ⊗ K B) is representation-infinite.…”
Section: 5mentioning
confidence: 99%