2000
DOI: 10.1007/bf02529642
|View full text |Cite
|
Sign up to set email alerts
|

On the rosenthal inequality for mixing fields

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
7
0

Year Published

2000
2000
2022
2022

Publication Types

Select...
5
1

Relationship

0
6

Authors

Journals

citations
Cited by 6 publications
(7 citation statements)
references
References 2 publications
0
7
0
Order By: Relevance
“…The result follows from a Rosenthal type inequality for mixing random fields, which was first suggested in this setting by Doukhan (1994). However, we have based our result on the slightly weaker version derived by Fazekas et al (2000), in order to control the constant C 1 more precisely. The theorem shows that the constant only depends on the mixing coefficients in a monotone fashion.…”
Section: C1 Technical Prerequisitesmentioning
confidence: 99%
“…The result follows from a Rosenthal type inequality for mixing random fields, which was first suggested in this setting by Doukhan (1994). However, we have based our result on the slightly weaker version derived by Fazekas et al (2000), in order to control the constant C 1 more precisely. The theorem shows that the constant only depends on the mixing coefficients in a monotone fashion.…”
Section: C1 Technical Prerequisitesmentioning
confidence: 99%
“…In addition, by (3), the last expression in the inequality is bounded. We may then adapt Theorem 1 in Fazekas, Kukush, and Tómács (2000) to the lattice s n Z d and so there exists a constant c 2 > 0 such that…”
Section: Proof Of Theoremmentioning
confidence: 99%
“…Then, by (2) and (C2), we may apply Theorem 1 in Fazekas et al (2000), which states the existence of c 1 > 0 such that…”
Section: Assumption (I)mentioning
confidence: 99%
“…Bolthausen [1] and Guyon [11] extended it to˛-mixing random fields. Fazekas [10] and Fazekas and Kukush [8] presented the so-called infill-increasing versions of Guyon's result for the bounded and the uniformly integrable cases, respectively. These papers do not contain the proofs of the theorems mentioned (a sketch of the proof can be found in [9]).…”
Section: Introductionmentioning
confidence: 99%
“…Then there is a constant c such that for any finite subset D of Z d .We remark that the proof of the Rosenthal inequality (2.11) follows from (2.12) below, by using the so-called interpolation lemma. Details and the general form of the Rosenthal inequality can be found, e. g., in[8].Remark 2. Using the notation of Lemma 2, let > 0, and assume that c…”
mentioning
confidence: 99%