2017
DOI: 10.1016/j.jet.2017.03.001
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On the set of extreme core allocations for minimal cost spanning tree problems

Abstract: Minimal cost spanning tree problems connect agents efficiently to a source when agents are located at different points and the cost of using an edge is fixed. We propose a method, based on the concept of marginal games, to generate all extreme points of the corresponding core. We show that three of the most famous solutions to share the cost of mcst problems, the Bird, folk and cycle-complete solutions, are closely related to our method.

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Cited by 19 publications
(16 citation statements)
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“…Proof. Correspondence between the cycle-complete solution andȳ is shown in Trudeau and Vidal-Puga (2017). We show the correspondence between the nucleolus and the cycle-complete solution.…”
Section: Minimum Cost Spanning Tree Games and Clique Gamesmentioning
confidence: 70%
“…Proof. Correspondence between the cycle-complete solution andȳ is shown in Trudeau and Vidal-Puga (2017). We show the correspondence between the nucleolus and the cycle-complete solution.…”
Section: Minimum Cost Spanning Tree Games and Clique Gamesmentioning
confidence: 70%
“…In [18,19] it is shown that for elementary mcst problems, the Folk solution is the permutationweighted average of the extreme points of the non-property rights game defined by v(S). Then, for any elementary mcst problem (N ω , C), as a consequence of Proposition 2 we obtain…”
Section: Some Further Commentsmentioning
confidence: 99%
“…. ., K, denote the extreme points of the core of the cooperative game defined by v(S) (see [18]). Moreover, in this class of mcst problems, β ceq also coincides with the nucleolus (see [19]), showing the close relationships between the egalitarian and nucleolus concepts.…”
Section: Some Further Commentsmentioning
confidence: 99%
“…冷漠参与人的存在可能会使得相应博弈的核为空. 文献 [22] 给出了最小支撑树博 弈核多面体所有的顶点, 并指出了最小支撑树博弈可能与指派博弈 (assignment games) 之间存在一定 的联系. 文献 [23] 研究了最小支撑树问题中的机制设计问题, 发现如果使用 Folk 配置分担成本, 那么 存在一个 Nash 均衡, 参与人都会真实报告自己的成本信息, 而使用 Bird 配置或者 DK 配置则不存在 这样的均衡.…”
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