2011
DOI: 10.1007/s11253-011-0510-3
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On the theory of convergence and compactness for Beltrami equations

Abstract: Theorems on convergence and compactness are proved for the classes of regular solutions of degenerate Beltrami equations with restrictions of integral type imposed on the dilatation.

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Cited by 10 publications
(6 citation statements)
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“…Then it is obvious that µ τ (z) = µ(z 0 + τ z), K µτ (z) = K µ (z 0 + τ z), and the approximative continuity of µ(z) at the point z 0 is equivalent to the convergence in measure µ τ → µ 0 = µ(z 0 ) as τ → 0. Thus, h τ → h 0 as τ → 0 by virtue of Theorem 2 and Lemma 2 in [24] with regard for (6.10), (6.5), and Corollary 6.1, cf. the estimate of the integral I τ in the proof of Theorem 6.1.…”
Section: ) F Is Conformal By Belinskii At Zero;mentioning
confidence: 88%
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“…Then it is obvious that µ τ (z) = µ(z 0 + τ z), K µτ (z) = K µ (z 0 + τ z), and the approximative continuity of µ(z) at the point z 0 is equivalent to the convergence in measure µ τ → µ 0 = µ(z 0 ) as τ → 0. Thus, h τ → h 0 as τ → 0 by virtue of Theorem 2 and Lemma 2 in [24] with regard for (6.10), (6.5), and Corollary 6.1, cf. the estimate of the integral I τ in the proof of Theorem 6.1.…”
Section: ) F Is Conformal By Belinskii At Zero;mentioning
confidence: 88%
“…We note also that f τ do not take values of 1 and ∞ inside D. Therefore, f τ , τ ∈ (0, τ 0 ], form a normal family (see Theorem 2 in [24]). Thus, f τ , τ ∈ (0, τ 0 ], is the equicontinuous family by Proposition 7.1 in [26].…”
Section: ) F Is Conformal By Belinskii At Zero;mentioning
confidence: 96%
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“…However, let us note that it is in the form given below that the indicated statement seems to be the most interesting from the point of view of applications to the problem of compactness of solutions of the Beltrami equations and the Dirichlet problem (see, for example, [Dyb,Theorem 2]) and [L,Theorem 1]).…”
Section: Introductionmentioning
confidence: 99%
“…Note that the relation (1.5) holds for the corresponding function K µ = K µ f (see e.g. [L,Lemma 1]). Therefore, f ∈ F M ϕ,Φ,z 0 (D).…”
mentioning
confidence: 99%