2019
DOI: 10.1016/j.jalgebra.2018.10.016
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On the uniform bound of Frobenius test exponents

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Cited by 14 publications
(11 citation statements)
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“…It leads the following question. We definite the Frobenius test exponent for parameter ideals of R, F te(R), the smallest integer e satisfying the above condition and F te(R) = ∞ if we have no such e. Question 1 has affirmative answers when R is either generalized Cohen-Macaulay by [7] or F -nilpotent by [14], and is open in general. The Frobenius test exponent for parameter ideals is closely related with an invariant defined in terms of Frobenius action on local cohomology.…”
Section: On the Frobenius Test Exponent For Parameter Idealsmentioning
confidence: 99%
See 1 more Smart Citation
“…It leads the following question. We definite the Frobenius test exponent for parameter ideals of R, F te(R), the smallest integer e satisfying the above condition and F te(R) = ∞ if we have no such e. Question 1 has affirmative answers when R is either generalized Cohen-Macaulay by [7] or F -nilpotent by [14], and is open in general. The Frobenius test exponent for parameter ideals is closely related with an invariant defined in terms of Frobenius action on local cohomology.…”
Section: On the Frobenius Test Exponent For Parameter Idealsmentioning
confidence: 99%
“…Furthermore, the authors of [7] confirmed the question for generalized Cohen-Macaulay local rings. Recently the second author gave a positive answer for the question for F -nilpotent rings [14]. The main idea in [7,8] Our main technique is to analyze the local cohomology modules by using the Nagel-Schenzel isomorphism (cf.…”
Section: Introductionmentioning
confidence: 99%
“…(2) Huneke, Katzman, Sharp and Yao [5] gave an affirmative answer for Question 1 for generalized Cohen-Macaulay rings. (3) Recently, the second author [14] provided a simple proof for the theorem of Huneke, Katzman, Sharp and Yao. By the same method he also proved that F te(R) < ∞ if R is F -nilpotent.…”
Section: Preliminariesmentioning
confidence: 99%
“…[8] F te(R) = HSL(R). Moreover the question of Katzman and Sharp has affirmative answers when R is either generalized Cohen-Macaulay by [5] or F -nilpotent by [14] (see the next section for the details). The main result of the present paper is as follows.…”
Section: Introductionmentioning
confidence: 99%
“…Beyond the Cohen-Macaulay case, Huneke, Katzman, Sharp, and Yao [8] showed that Fte(R) < ∞ for generalized Cohen-Macaulay local rings by using several concepts and techniques from commutative algebra, namely unconditioned strong d-sequences, cohomological annihilators, and modules of generalized fractions. In 2019, the second author [16] not only simplified the proof for generalized Cohen-Macaulay rings but also proved Fte(R) < ∞ for weakly F-nilpotent rings, i.e. [13] extended this result for generalized weakly F-nilpotent rings, i.e.…”
Section: Introductionmentioning
confidence: 99%