2009
DOI: 10.1103/physrevlett.102.135003
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One-Dimensional Vlasov-Maxwell Equilibrium for the Force-Free Harris Sheet

Abstract: In this Letter, the first nonlinear force-free Vlasov-Maxwell equilibrium is presented. One component of the equilibrium magnetic field has the same spatial structure as the Harris sheet, but whereas the Harris sheet is kept in force balance by pressure gradients, in the force-free solution presented here force balance is maintained by magnetic shear. Magnetic pressure, plasma pressure and plasma density are constant. The method used to find the equilibrium is based on the analogy of the one-dimensional Vlasov… Show more

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Cited by 69 publications
(162 citation statements)
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“…Recently the first nonlinear force-free, non-relativistic VM equilibrium for the force-free Harris sheet was reported by Harrison and Neukirch 9 . If the thermal energy of the plasma approaches or exceeds its rest energy, a non-relativistic treatment is no longer sufficient and a relativistic analogue must be sought.…”
Section: Discussionmentioning
confidence: 99%
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“…Recently the first nonlinear force-free, non-relativistic VM equilibrium for the force-free Harris sheet was reported by Harrison and Neukirch 9 . If the thermal energy of the plasma approaches or exceeds its rest energy, a non-relativistic treatment is no longer sufficient and a relativistic analogue must be sought.…”
Section: Discussionmentioning
confidence: 99%
“…This paper has presented a collisionless distribution function for the relativistic force-free Harris sheet. Mirroring the non-relativistic solution [9][10][11] , where the properties of the pressure tensor were exploited, the energy-momentum tensor T αβ was wielded in an equivalent role 27 , allowing the calculation of the equilibrium. In our Alternative methods of studying relativistic VM equilibria have also been developed [28][29][30][31][32][33][34] .…”
Section: Discussionmentioning
confidence: 99%
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“…For the method to work one has to ensure that 0 [3,31,32]) for all possible values of A x , A y . This imposes additional conditions which the parameters of the distribution function have to satisfy.…”
Section: Basic Theorymentioning
confidence: 99%