“…Here, using the terminology of [21], the feedback is allowed to be weak, i.e., g(s)/s can go to 0 as |s| goes to infinity, as it is the case when g represents a saturation mapping; then, loss of uniformity is to be expected. More precisely, coming back to the Neumann problem, the one-dimensional version of (1.6) with g given by (1.7) is known to possess weak solutions that decay to zero (in the natural energy space H 1 (Ω) × L 2 (Ω)) slower than any exponential or polynomial, whereas strong solutions decay exponentially to zero but in a non-uniform way -see [21,Theorem 4.1] or also [1,Theorem 4.33]. Proving a similar result in our Dirichlet case would be interesting.…”