2017
DOI: 10.48550/arxiv.1711.08648
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Operator-stable and operator-self-similar random fields

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“…Moreover, if µ = µ s is still constant but operator-stable (say with exponent B), we also get back the setting of [11]. Merely note that, in contrast to [11], µ has to be symmetric (instead of strictly) operator-stable in our framework. However, τ = τ s does not depend on s ∈ S either and (2.14) becomes…”
Section: Multi Operator-stable Random Measures and Integralsmentioning
confidence: 91%
See 4 more Smart Citations
“…Moreover, if µ = µ s is still constant but operator-stable (say with exponent B), we also get back the setting of [11]. Merely note that, in contrast to [11], µ has to be symmetric (instead of strictly) operator-stable in our framework. However, τ = τ s does not depend on s ∈ S either and (2.14) becomes…”
Section: Multi Operator-stable Random Measures and Integralsmentioning
confidence: 91%
“…Recall Remark 2.3 and that µ s ∼ [0, 0, ϕ(s, •)] with ϕ(s, •) being symmetric for every s ∈ S. Then (a) and (b) follow immediately from Proposition 3.3 and section 5 of [10], respectively. Also recall that µ s is full for every s ∈ S. Hence, using (2.13) and Lemma 1.3.11 in [14], a slight refinement of Proposition 2.6 (a) in [11] gives part (c). The details are left to the reader.…”
Section: Multi Operator-stable Random Measures and Integralsmentioning
confidence: 94%
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