2006
DOI: 10.4134/bkms.2006.43.3.509
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Operators With the Single Valued Extension Property

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Cited by 13 publications
(10 citation statements)
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“…We combine the equations (12) and (13) to obtain A n = A n+1 for every nonnegative integer n, and from (12) we get that A n = 1 for every nonnegative integer n. This implies β n = α n for every nonnegative integer n. Thus we have W = R. □ …”
Section: Some Applications In Weighted Shiftsmentioning
confidence: 99%
See 2 more Smart Citations
“…We combine the equations (12) and (13) to obtain A n = A n+1 for every nonnegative integer n, and from (12) we get that A n = 1 for every nonnegative integer n. This implies β n = α n for every nonnegative integer n. Thus we have W = R. □ …”
Section: Some Applications In Weighted Shiftsmentioning
confidence: 99%
“…(1) Assume that at least one of the equalities σ(R) = σ e (R) = σ le (R) fails to hold or σ le (R) ̸ = σ re (R). Since σ R (x) ⊂ σ S (x) for all x ∈ H by Corollary 3.4.5 in [14] and R has the single valued extension property, it follows from [12] and [14] that S has the single valued extension property,…”
Section: Spectral Propertiesmentioning
confidence: 99%
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“…If S ∈ Helton k (R) and R has the single valued extension property, then S has the single valued extension property from [7]. Next, let f (λ) be an analytic function which verifies (λ − S)f (λ) = x.…”
Section: Lemma 29 ([8]) If R Has the Single Valued Extension Propermentioning
confidence: 99%
“…(4) By [7], S has the single valued extension property. Assume that x and y are any vectors in H such that σ S (x) ∩ σ S (y) = ∅.…”
Section: Then W(r) = R(r) Since R(s) ≤ W(s) By [5] We Get That W(r)mentioning
confidence: 99%