2017
DOI: 10.1016/j.endm.2017.06.019
|View full text |Cite
|
Sign up to set email alerts
|

Packing degenerate graphs greedily

Abstract: We prove that if G is a family of graphs with at most n vertices each, with constant degeneracy, with maximum degree at most O (n/ log n), and with total number of edges at most, then G packs into the complete graph K n .

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2

Citation Types

0
4
0

Year Published

2018
2018
2020
2020

Publication Types

Select...
2

Relationship

1
1

Authors

Journals

citations
Cited by 2 publications
(4 citation statements)
references
References 5 publications
0
4
0
Order By: Relevance
“…We choose the J(v i ) to be uniformly distributed 2 over [ñ], and such that for most v i the intervals J(v i ) 2 A technical complication arises in that the extremes of the interval [ñ] are not covered as much as the rest; we will ignore this for now. and J(v j ), where v j is the parent of v i in the ordering, are equally far from and on opposite sides of 1 2 (1 + γ)n. In reality, we certainly do not choose vertex labels uniformly at random in the intervals; there is a great deal of dependency in the label choices. However, that dependency is sequential: conditioning on the labelling history of the first t − 1 vertices, we know the distribution of the t th vertex, and we will be able to show that the average of these distributions is close to uniform (in a sense which we will make precise later).…”
Section: Setupmentioning
confidence: 99%
See 3 more Smart Citations
“…We choose the J(v i ) to be uniformly distributed 2 over [ñ], and such that for most v i the intervals J(v i ) 2 A technical complication arises in that the extremes of the interval [ñ] are not covered as much as the rest; we will ignore this for now. and J(v j ), where v j is the parent of v i in the ordering, are equally far from and on opposite sides of 1 2 (1 + γ)n. In reality, we certainly do not choose vertex labels uniformly at random in the intervals; there is a great deal of dependency in the label choices. However, that dependency is sequential: conditioning on the labelling history of the first t − 1 vertices, we know the distribution of the t th vertex, and we will be able to show that the average of these distributions is close to uniform (in a sense which we will make precise later).…”
Section: Setupmentioning
confidence: 99%
“…Because n is divisible by 2δ −4 0 γ −1 , and δ −1 0 is an integer, ℓ, m For each J ∈ J , we define the complementary interval J ∈ J to be the (unique) interval J such that the sum of the elements of J ∪ J is ℓ(ñ + 1). By definition, J and J are disjoint, one having only elements less than or equal to 1 2 ñ and the other having only elements greater than 1 2 ñ.…”
Section: Setupmentioning
confidence: 99%
See 2 more Smart Citations