2014
DOI: 10.1021/am504127k
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Palladium Nanoparticle Formation on TiO2(110) by Thermal Decomposition of Palladium(II) Hexafluoroacetylacetonate

Abstract: Palladium nanoparticles were synthesized by thermal decomposition of palladium(II) hexafluoroacetylacetonate (Pd(hfac)2), an atomic layer deposition (ALD) precursor, on a TiO2(110) surface. According to X-ray photoelectron spectroscopy (XPS), Pd(hfac)2 adsorbs on TiO2(110) dissociatively yielding Pd(hfac)(ads), hfac(ads), and adsorbed fragments of the hfac ligand at 300 K. A (2 × 1) surface overlayer was observed by scanning tunneling microscopy (STM), indicating that hfac adsorbs in a bidentate bridging fashi… Show more

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Cited by 44 publications
(50 citation statements)
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“…The adsorbate coverage is determined from XP models as outlined in Ref. [32][33][34][35]. In order to validate the CVD-based catalytic results and to obtain a broader experimental basis of the Pd-Zr 0 system with respect to methanol steam reforming performance, also an intermetallic bulk phase of …”
Section: Preparation Of Materialsmentioning
confidence: 99%
“…The adsorbate coverage is determined from XP models as outlined in Ref. [32][33][34][35]. In order to validate the CVD-based catalytic results and to obtain a broader experimental basis of the Pd-Zr 0 system with respect to methanol steam reforming performance, also an intermetallic bulk phase of …”
Section: Preparation Of Materialsmentioning
confidence: 99%
“…A detailed understanding of ferrocene adsorption and oxidation, as well as the formation of monolayer thick FeO islands on Pt(111), is developed here using a suite of Ultra High Vacuum (UHV) surface sensitive techniques, whose efficacy has been established in previous studies of vacuum ALD. [38][39][40][41][42] …”
Section: Introductionmentioning
confidence: 99%
“…First, the position of this peak is consistent with the fluorine still being attached to carbon rather than with the formation of Cu− −F species. 22,52 Thus, it is likely that the source of the remaining fluorine is the − −CF 3 groups of the hfac. Second, the Cu/F ratio is calculated to be 1:1 again for Cu(hfac) 2 while that for Cu(hfac)VTMS is found to be approximately 4:1.…”
Section: Resultsmentioning
confidence: 99%