2021
DOI: 10.48550/arxiv.2107.02116
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Parking on Cayley trees & Frozen Erdös-Rényi

Alice Contat,
Nicolas Curien

Abstract: Consider a uniform rooted Cayley tree T n with n vertices and let m cars arrive sequentially, independently, and uniformly on its vertices. Each car tries to park on its arrival node, and if the spot is already occupied, it drives towards the root of the tree and parks as soon as possible. Lackner & Panholzer [56] established a phase transition for this process when m ≈ n 2 . In this work, we couple this model with a variant of the classical Erdős-Rényi random graph process. This enables us to describe the pha… Show more

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Cited by 5 publications
(11 citation statements)
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“…Section 4 is devoted to the study of F via a functional equation obtained by splitting a fully parked tree at the root, see (10). But before doing so, let us present the combinatorial decomposition and the characterization of subcriticality in terms of F. It turns out that most equations simplify if one introduces F(x, y) := 1 + F(x, y) and F 0 (x) := F(x, 0) := 1 + F(x, 0).…”
Section: Fully Parked Treesmentioning
confidence: 99%
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“…Section 4 is devoted to the study of F via a functional equation obtained by splitting a fully parked tree at the root, see (10). But before doing so, let us present the combinatorial decomposition and the characterization of subcriticality in terms of F. It turns out that most equations simplify if one introduces F(x, y) := 1 + F(x, y) and F 0 (x) := F(x, 0) := 1 + F(x, 0).…”
Section: Fully Parked Treesmentioning
confidence: 99%
“…To solve this equation, we apply the kernel method of Bousquet-Mélou and Jehanne [4] and look for a (formal) power series Y = Y(x) such that ∂ f P(F(x, Y(x)), F 0 (x), x, Y(x)) = 0 so that combined with (10) we also find automatically ∂ y P(F(x, Y(x)), F 0 (x), x, Y(x)) = 0. This introduction may seem ad-hoc, but it enables us to find a system of three equations on the three unknowns F, F 0 and Y, so that with a little luck we will find an "expression" for those.…”
Section: Solving Tutte's Equationmentioning
confidence: 99%
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